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Debugger always steps into CreateForm

Publicado: Mar Jul 11, 2006 3:22 pm
por Oleg
Jose,
I debug my first examples and I noticed that when I debug code like this:
func OpenWait(ow)
local oForm, a, aS1, nWidth:=0, i, nTmp
a:=Str2Array(cText, ';')
oForm:=TFormWait():New(Application:oMainForm) // this line
...
return NIL
debugger always step into TFormWait:CreateForm (from .xfm file) unless I
always press {F8} (Step over).
Is it correct behavior? I think that it is more correct to step into it if I
press {F7} and step over if I press {F8}.
Thank you. Oleg.

Debugger always steps into CreateForm

Publicado: Mar Jul 11, 2006 5:21 pm
por jfgimenez
Oleg,
> I debug my first examples and I noticed that when I debug code like this:
>
> func OpenWait(ow)
> local oForm, a, aS1, nWidth:=0, i, nTmp
> a:=Str2Array(cText, ';')
> oForm:=TFormWait():New(Application:oMainForm) // this line
> ...
> return NIL
>
> debugger always step into TFormWait:CreateForm (from .xfm file) unless I
> always press {F8} (Step over).
> Is it correct behavior? I think that it is more correct to step into it if
> I
> press {F7} and step over if I press {F8}.
I'll review it ASAP. Thanks for the info.
--
Regards,
Jose F. Gimenez
http://www.xailer.com

Debugger always steps into CreateForm

Publicado: Mar Jul 11, 2006 5:21 pm
por jfgimenez
Oleg,
> I debug my first examples and I noticed that when I debug code like this:
>
> func OpenWait(ow)
> local oForm, a, aS1, nWidth:=0, i, nTmp
> a:=Str2Array(cText, ';')
> oForm:=TFormWait():New(Application:oMainForm) // this line
> ...
> return NIL
>
> debugger always step into TFormWait:CreateForm (from .xfm file) unless I
> always press {F8} (Step over).
> Is it correct behavior? I think that it is more correct to step into it if
> I
> press {F7} and step over if I press {F8}.
I'll review it ASAP. Thanks for the info.
--
Regards,
Jose F. Gimenez
http://www.xailer.com